No Idea hackerrank solution
Hi,
Here I solve the No Idea hackerrank solution in Python.Problem - No Idea hackerrank solution
There is an array of integers. There are also disjoint sets, and , each containing integers. You like all the integers in set and dislike all the integers in set . Your initial happiness is . For each integer in the array, if , you add to your happiness. If , you add to your happiness. Otherwise, your happiness does not change. Output your final happiness at the end.
Note: Since and are sets, they have no repeated elements. However, the array might contain duplicate elements.
Constraints
Input Format
The first line contains integers and separated by a space.
The second line contains integers, the elements of the array.
The third and fourth lines contain integers, and , respectively.
The second line contains integers, the elements of the array.
The third and fourth lines contain integers, and , respectively.
Output Format
Output a single integer, your total happiness.
Sample Input
3 2
1 5 3
3 1
5 7
Sample Output
1
Explanation
You gain unit of happiness for elements and in set . You lose unit for in set . The element in set does not exist in the array so it is not included in the calculation.
Hence, the total happiness is .
No Idea hackerrank solution !
n,m = [int(x) for x in input().split()]
p = [int(x) for x in input().split()]
a = {int(x) for x in input().split()}
b = {int(x) for x in input().split()}
h = 0
for x in p:
if x in a:
h = h + 1
elif x in b:
h = h - 1
print(h)
Hope I helped you with the No Idea hackerrank solution.
Happy to help.
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